XTRXTR
Well-Known Member
Curious if anyone has plate resistors installed in series between plate Pin 3 and CT on their builds?
The point is to be able to measure the current via voltage setting on the meter just like the cathode. I would put in test points on either side of the resistors on the top of my DIY chassis with the bias pots accessible without opening chassis. Gives the ability to measure plate current directly while dialing the dual neg voltage bias pots.
What watt rating should I consider if I do this?
AC can swing at what Vpp for the V^2/R power calc?
El34 data sheet says 2x95mA Ia at max signal so I^2R. But at R=1 Ohm: I^2R = V^2/R = P in watts.
.095^2x1 = .095^2/1 = .095^2 = 0.009025 watts = 9mW
But if I look at the Max cathode current 150mA then just state that as a worse case that the plate current is the same as cathode current to build in some error for the watt rating. Then 0.150^2 = 22.5mW. Thus the .25 watt plate to CT series resistor is .25/.0225 = 11 times the operating power needed for EL34.
What about if I run some other tube that can run higher currents later on when I forget that I have a 1/4watt resistor in that position?
KT66 200mA max cathode current
KT77 200mA max cathode current
KT120 250mA max cathode current
6550 175mA max cathode current
5881 140mA max plate current same as 6L6
Okay good enough 250mA max .250^2 = 62.5mW is 4 times the Max operating power. That is within the 4 times the size general rule. And if more current flowed it would likely mean a tube failure is happening. So 1/4 watt would act as protection to the OT if it failed open as it should. And I always run tubes cool 55% to 60%.
What do you think? Build it in? yes , no , why not?
Discuss
The point is to be able to measure the current via voltage setting on the meter just like the cathode. I would put in test points on either side of the resistors on the top of my DIY chassis with the bias pots accessible without opening chassis. Gives the ability to measure plate current directly while dialing the dual neg voltage bias pots.
What watt rating should I consider if I do this?
AC can swing at what Vpp for the V^2/R power calc?
El34 data sheet says 2x95mA Ia at max signal so I^2R. But at R=1 Ohm: I^2R = V^2/R = P in watts.
.095^2x1 = .095^2/1 = .095^2 = 0.009025 watts = 9mW
But if I look at the Max cathode current 150mA then just state that as a worse case that the plate current is the same as cathode current to build in some error for the watt rating. Then 0.150^2 = 22.5mW. Thus the .25 watt plate to CT series resistor is .25/.0225 = 11 times the operating power needed for EL34.
What about if I run some other tube that can run higher currents later on when I forget that I have a 1/4watt resistor in that position?
KT66 200mA max cathode current
KT77 200mA max cathode current
KT120 250mA max cathode current
6550 175mA max cathode current
5881 140mA max plate current same as 6L6
Okay good enough 250mA max .250^2 = 62.5mW is 4 times the Max operating power. That is within the 4 times the size general rule. And if more current flowed it would likely mean a tube failure is happening. So 1/4 watt would act as protection to the OT if it failed open as it should. And I always run tubes cool 55% to 60%.
What do you think? Build it in? yes , no , why not?
Discuss