I did a quick Google but didn't really find anything. Both my JVM205 and SV20 have three "sets" of speaker jacks- 1-16 ohm, 2- 16 ohm (8 ohm load), and 2- 8 ohm (4 ohm load) speaker outs. I get that I plug two 16 ohm cabs into the 2- 16 ohm outputs to have a safe 8 ohm load on the amp. But what's the proper method of plugging an 8 ohm and a 16 ohm cab?
I'm guessing one cab into one of the two 16 Ohm sets and one cab into one of the two 8 ohm sets. But I don't wanna guess!!
Do you mean connecting both a 16 ohm and a 8 ohm cabinet at the same time? If so, the 16 ohm cabinet gets plugged into an 8 ohm output jack and the 8 ohm cabinet gets plugged into a 4 ohm output jack.
If you use 16 ohm + 8 ohm, the total is 5.3 ohms. The amp must be set 4 ohm out to run that load. Speakers formula Speaker 1 X speaker 2 -------------------------- = total load Speaker 1 + speaker 2
Any amp with multiple outputs including SJ Reissues can be used in this way. Amps with an impedance switch cannot.
Wait, so on those modern Marshalls with all those cabinet configuration jacks, you can use speakers of different ohms? I always thought that was a no no. Good to know I can plug my 16ohm 4x12 and my 8ohm 2x12 cabs into my JMD. Is this right? Edit: looks like the JMD does nit have a 4ohm out.
its cool, and was confirmed for us years ago by Santiago (JVM desgner) on this forum Each speaker goes to an amp tap of half its ohm rating, and hence each provides half the load that the amp needs, and each gets half the power. All perfectly good and logical. Its not put in the manuals though, too hard to reliably explain to the average Joe Rocker.